4q+2q=3q^2-4q+16

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Solution for 4q+2q=3q^2-4q+16 equation: 



4q+2q=3q^2-4q+16

We move all terms to the left:

4q+2q-(3q^2-4q+16)=0

We add all the numbers together, and all the variables

6q-(3q^2-4q+16)=0

We get rid of parentheses

-3q^2+6q+4q-16=0

We add all the numbers together, and all the variables

-3q^2+10q-16=0

a = -3; b = 10; c = -16;
Δ = b2-4ac
Δ = 102-4·(-3)·(-16)
Δ = -92
Delta is less than zero, so there is no solution for the equation

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